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## A 60 cm diameter potter’s wheel with a mass of 30 kg is spinning at 180 rpm. Using her hands, a potter forms a 14 cm-diameter pot that is ce

Question

A 60 cm diameter potter’s wheel with a mass of 30 kg is spinning at 180 rpm. Using her hands, a potter forms a 14 cm-diameter pot that is centered on and attached to the wheel. The pot’s mass is negligible compared to that of the wheel. As the pot spins, the potter’s hands apply a net frictional force of 1.3 N to the edge of the pot. If the power goes out, so that the wheels motor no longer provides any torque, how long will it take the wheel to come to a stop? You can assume that the wheel rotates on frictionless bearings and that the potter keeps her hands on the pot as it slows.

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Physics
2 weeks
2021-08-28T18:25:07+00:00
2021-08-28T18:25:07+00:00 1 Answers
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## Answers ( )

Answer:It will take the wheel

278.9 sto come to a stopExplanation:Mass of the potter’s wheel, M = 30 kg

Diameter of the potter’s wheel, d₁ = 60 cm = 0.6 m

Radius, r₁ = d/2 = 0.6/2

r₁ = 0.3 m

The moment of inertia of the wheel,

d₂ = 14 cm = 0.14 m

r₂ = 0.14/2 = 0.07 m

Angular velocity,

Frictional Force, F = 1.3 N

The torque generated:

Torque can also be calculated as: