A 60.0-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.57 m, and ends

Question

A 60.0-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.57 m, and ends with a speed of 8.50 m/s. How much nonconservative work was done on the boy

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Thái Dương 4 years 2021-08-25T09:30:39+00:00 1 Answers 10 views 0

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  1. thienthi
    0
    2021-08-25T09:32:25+00:00
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    Answer:

    Work = 1167.54 J

    Explanation:

    The amount of non-conservative work here can be given by the difference in kinetic energy and the potential energy. From Law of conservation of energy, we can write that:

    Gain in K.E = Loss in P.E + Work

    (0.5)(m)(Vf² – Vi²) – mgh = Work

    where,

    m = mass of boy = 60 kg

    Vf = Final Speed = 8.5 m/s

    Vi = Initial Speed = 1.6 m/s

    g = 9.8 m/s²

    h = height drop = 1.57 m

    Therefore,

    (0.5)(60 kg)[(8.5 m/s)² – (1.6 m/s)²] – (60 kg)(9.8 m/s²)(1.57 m) = Work

    Work = 2090.7 J – 923.16 J

    Work = 1167.54 J

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