A 55 g soapstone cube–a whisky stone–is used to chill a glass of whisky. Soapstone has a density of 3000 kg/m3, whisky a density of 940 kg

Question

A 55 g soapstone cube–a whisky stone–is used to chill a glass of whisky. Soapstone has a density of 3000 kg/m3, whisky a density of 940 kg/m3. What is the approximate normal force of the bottom of the glass on a single stone?

in progress 0
Nem 4 years 2021-07-13T10:38:06+00:00 1 Answers 15 views 0

Answers ( )

  1. Acacia
    0
    2021-07-13T10:39:21+00:00
    Reply

    Answer:

    N=0.37N

    Explanation:

    Mass m=55g=>0.055kg

    Soapstone Density \rho_s=3000kg/m^2

    Whisky Density \rho_w=940kg/m^2

    Generally the equation for Force is mathematically given by

     F=U+N

    Therefore

     N=m*g-(\frac{m}{\rho_s})*\rho_w*g

     N=0.055*9.81 - {(\frac{0.055}{3000})*940*9.81}

     N=0.37N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )