. A 500-Ω resistor, an uncharged 1.50-μF capacitor, and a 6.16-V emf are connected in series. (a) What is the initial current? (b) What is t

Question

. A 500-Ω resistor, an uncharged 1.50-μF capacitor, and a 6.16-V emf are connected in series. (a) What is the initial current? (b) What is the RC time constant? (c) What is the current after one time constant? (d) What is the voltage on the capacitor after one time constant?

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Ngọc Hoa 1 year 2021-08-21T06:54:10+00:00 2 Answers 166 views 0

Answers ( )

    0
    2021-08-21T06:55:32+00:00

    Answer:

    initial current I₀ = 0.0123 A

    RC time constant τ = 0.00075 sec

    current after one time constant I = 0.00452 A

    voltage on the capacitor after one time constant V = 3.89 V

    Explanation:

    Given that,

    Voltage = 6.16 V

    Resistance = 500 Ω

    Capacitance = 1.5 µF  

    (a) What is the initial current?

    The initial current can be found using

    I₀ = Voltage/Resistance

    I₀ = 6.16/500

    I₀ = 0.0123 A

    (b) What is the RC time constant?

    The time constant τ provides the information about how long it will take to charge the capacitor.

    τ = R*C

    τ = 500*1.5×10⁻⁶

    τ = 0.00075 sec

    (c) What is the current after one time constant?

    I = I₀e^(-τ/RC)

    I = 0.0123*e^(-1)   (0.00075/0.00075 = 1)

    I = 0.00452 A

    (d) What is the voltage on the capacitor after one time constant?

    V = V₀(1 – e^(-τ/RC))

    Where V₀ is the initial voltage 6.16 V

    V = 6.16(1 – e^(-1))

    V = 6.16*0.63212

    V = 3.89 V

    That means the capacitor will charge up to 3.89 V in one time constant

    0
    2021-08-21T06:56:06+00:00

    Answer:

    Explanation:

    Given an RC circuit to analyze

    R=500Ω

    C=1.50-μF uncharged

    Emf(V)=6.16V

    Series connection

    a. Initial current, since the capacitor is initially uncharged then, the voltage appears at the resistor

    Using ohms law

    V=iR

    Then, i=V/R

    i=6.16/500

    i=0.01232 Amps

    i=12.32 mA.

    b. The time constant is given as

    τ=RC

    τ=500×1.5×10^-6

    τ=0.00075second

    τ=0.75 ms

    c. What is current after 1 time constant

    Current in a series RC circuit is given as

    Time after I time constant is

    t=1 ×τ

    t= τ

    i=V/R exp(-t/RC)

    Where RC= τ

    i=V/Rexp(-t/ τ)

    i=6.16/500exp(-1), since t= τ

    i=0.004532A

    I=4.532mA

    d. Voltage after one time constant

    Voltage of a series RC circuit(charging) is given as

    Again, t= τ

    V=Vo(1 – exp(-t/ τ)),

    V=6.16(1-exp(-1))

    V=6.16(1-0.3679)

    V=6.16×0.632

    V=3.89Volts

    V=3.89V

    V=

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