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A 5 kg block is sliding on a horizontal surface while being pulled by a child using a rope attached to the center of the block. The rope exe
Question
A 5 kg block is sliding on a horizontal surface while being pulled by a child using a rope attached to the center of the block. The rope exerts a constant force of 28.2 N at an angle of \theta=θ = 30 degrees above the horizontal on the block. Friction exists between the block and supporting surface (with \mu_s=\:μ s = 0.25 and \mu_k=\:μ k = 0.12 ). What is the horizontal acceleration of the block?
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4 years
2021-08-13T04:14:55+00:00
2021-08-13T04:14:55+00:00 1 Answers
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Answer:
The horizontal acceleration of the block is 4.05 m/s².
Explanation:
The horizontal acceleration can be found as follows:
Where:
a: is the acceleration
F: is the force exerted by the rope = 28.2 N
θ: is the angle = 30°
m: is the mass = 5 kg
g: is the gravity = 9.81 m/s²
Therefore, the horizontal acceleration of the block is 4.05 m/s².
I hope it helps you!