A 5 g lead bullet traveling at 300 m/s is stopped by a large tree. If half the kinetic energy of the bullet is transformed into internal ene

Question

A 5 g lead bullet traveling at 300 m/s is stopped by a large tree. If half the kinetic energy of the bullet is transformed into internal energy and remains with the bullet while the other half is transmitted to the tree, what is the increase in the temperature of the bullet? Assume the specific heat of lead is 128 J/kg°C.

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Adela 1 week 2021-07-22T07:22:41+00:00 1 Answers 1 views 0

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    2021-07-22T07:23:57+00:00

    Answer:

    ∆temperature = 175781.25°

    Explanation:

    Kinetic energy = 1/2 * mv²

    Kinectic energy= 1/2 * 5 * 300²

    Kinectic energy = 2.5 * 90000

    Kinectic energy= 225000 joules.

    If half is transmitted to tree..

    If 225000/2 = 112500 joules

    Mc∆temperature = energy

    Mc∆temperature = 112500

    ∆temperature = 112500/mc

    ∆temperature= (112500)/((5/1000)*128)

    ∆temperature= 112500/0.64

    ∆temperature = 175781.25°

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