A 5.4 kg bowling ball and a 2.7 gram ping-pong ball collide head-on. If the magnitude of the force by the bowling ball on the ping-pong ball

Question

A 5.4 kg bowling ball and a 2.7 gram ping-pong ball collide head-on. If the magnitude of the force by the bowling ball on the ping-pong ball is 3.5 N, what is the magnitude of the force by the ping-pong ball on the bowling ball

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RuslanHeatt 2 months 2021-07-23T05:21:32+00:00 1 Answers 6 views 0

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    2021-07-23T05:22:40+00:00

    Answer:

    The magnitude of force of the ping-pong ball on the bowling ball , F_p = 3.5 N

    Explanation:

    Given;

    mass of the bowling ball, m_b = 5.4 kg

    mass of the ping-pong ball, m_p = 2.7 g = 0.0027 kg

    magnitude of force of the bowling ball, F_b = 3.5 N

    let the magnitude of force of ping-pong ball = F_p

    Apply Newton’s third law of motion; action and reaction are equal and opposite.

    F_b = -F_p

    The force of the ping-pong ball on the bowling ball is equal to that of the bowling ball on ping-pong ball, but in opposite direction.

    Thus, the magnitude of force of the ping-pong ball on the bowling ball , F_p = 3.5 N

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