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## – A 5.00-kg body accelerates from 3.25 m/s to 9.75 m/s in 3.0 seconds when a force acts upon it. Find (a) the change in momentum

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A 5.00-kg body accelerates from 3.25 m/s to 9.75 m/s in 3.0 seconds when a force acts upon it. Find (a) the change in momentum of the body, (b) the impulse produced by the force, and (c) the magnitude of the force.

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Physics
2 months
2021-07-26T00:17:44+00:00
2021-07-26T00:17:44+00:00 2 Answers
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## Answers ( )

Answer:(a) the change in momentum of the body is

32.5 kg.m/s(b) the impulse produced by the force is

32.5 N.s(c) the magnitude of the force is

10.83 NExplanation:Given;

mass of the body, m = 5.00-kg

initial velocity of the body, u = 3.25 m/s

final velocity of the body, v = 9.75 m/s

time taken, t = 3.0 seconds

Part (a)the change in momentum of the bodyΔP = mv – mu

= (5 x 9.75) – (5 x 3.25)

= 48.75 – 16.25

=

32.5 kg.m/sPart (b)the impulse produced by the forceI = f x t

where;

I is impulse

f is the applied force

t is time

f x t = mΔv

I = mΔv

I = m (v -u)

I = 5 (9.75 – 3.25)

I =

32.5 N.sPart (c)the magnitude of the force;I = f x t

f = I / t

where;

f is magnitude of the force.

I is impulse

t is time

f = 32.5 / 3

f =

10.83 NAnswer:(a)32.5 kgm/s(b)32.5 Ns(c)10.8 NExplanation:The change in momentum can be calculated from the definition of linear momentum:

Then, the change in momentum of the body is of 32.5 kgm/s

(a).Now, from the impulse-momentum theorem, we know that the change in momentum of a body is equal to the impulse exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns)

(b).Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:

It means that the magnitude of the force is of 10.8N

(c).