A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice bloc

Question

A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force isA 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force is

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niczorrrr 3 years 2021-08-08T11:11:54+00:00 1 Answers 117 views 0

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  1. diemthu
    0
    2021-08-08T11:13:12+00:00
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    Answer:

    Explanation:

    work done by applied force

    = force x displacement

    = 7.6 x 15 m

    = 114 J .

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