A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 seconds? (Hint: T

Question

A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 seconds? (Hint: This is a multi-step calculation and your answer should come out to be negative). Write your answer to one decimal place.

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Yến Oanh 2 weeks 2021-07-21T05:14:07+00:00 1 Answers 0 views 0

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    2021-07-21T05:15:48+00:00

    Answer:

    Force = -91.7 Newton

    Explanation:

    Given the following data;

    Mass = 47 kg

    Time = 4.1 seconds

    Initial velocity = 8 m/s

    Since the object comes to a stop, its final velocity would be equal to zero.

    To find the force required to bring it to stop;

    First of all, we would determine the acceleration of the object;

    Mathematically, acceleration is given by the equation;

    Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

    Substituting into the equation;

    a = \frac{0 - 8}{4.1}

    a = \frac{-8}{4.1}

    Acceleration, a = -1.95 m/s²

    Next, we would determine the force required to bring the object to stop;

     Force = mass * acceleration

     Force = 47 * -1.95

    Force = -91.65 ≈ 91.7 Newton

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