​A 460-turn solenoid of length 30.0 cm and radius 4.00 cm carries a current of 3.50 A. What is the magnetic field strength inside the coil a

Question

​A 460-turn solenoid of length 30.0 cm and radius 4.00 cm carries a current of 3.50 A. What is the magnetic field strength inside the coil at its midpoint? What is the magnetic field strength inside the coil at its midpoint?

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Orla Orla 5 months 2021-08-17T07:30:18+00:00 1 Answers 4 views 0

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    2021-08-17T07:32:00+00:00

    Answer:

    Magnetic field at the mid point of coil is 6.74 x 10⁻³ T

    Explanation:

    Given :

    Current flowing through the solenoid, I = 3.50 A

    Length of the solenoid, L = 30 cm = 0.3 m

    Number of turns in the solenoid, N = 460

    Magnetic field inside the coil at its mid point is given by the relation:

    B = μ₀nI    …(1)

    So, equation (1) becomes:

    B=\mu_{0}\frac {N}{L}I

    Substitute the suitable values in the above equation.

    B=4\pi\times10^{-7}\times  \frac {460}{0.3}\times3.50

    B = 6.74 x 10⁻³ T

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