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A 43.9-g piece of copper (CCu= 0.385 J/g°C) at 135.0°C is plunged into 254 g of water at 39.0°C. Assuming that no heat is lost to the surrou
Question
A 43.9-g piece of copper (CCu= 0.385 J/g°C) at 135.0°C is plunged into 254 g of water at 39.0°C. Assuming that no heat is lost to the surroundings, what will the final temperature of the system be?
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Physics
3 years
2021-08-24T04:10:12+00:00
2021-08-24T04:10:12+00:00 2 Answers
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Answer:
40.497 °C
Explanation:
Heat lost by copper = heat gained by water
CM(T₁-T₃) = cm(T₃-T₂)…………………… Equation 1
Where C = specific heat capacity of copper, M = mass of copper, T₁ = Initial Temperature of copper, T₂ = Initial Temperature of water, T₃ = final temperature of the system,
Make T₃ the subject of the equation
T₃= (CMT₁+cmT₂)/(CM+cm)…………….. Equation 2
Given: C = 0.385 J/g°C, M = 43.9 g, c = 4.2 J/g°C, m = 254 g, T₁ = 135 °C, T₂ = 39 °C
Substitute into equation 2
T₃ = (0.385×43.9×135+4.2×254×39)/(0.385×43.9+4.2×254)
T₃ = (2281.70+41605.2)/(16.9015+1066.8)
T₃ = 43886.9/1083.7015
T₃ = 40.497 °C.
Hence the final temperature of the system = 40.497 °C
Answer:
Explanation:
The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:
After a quick substitution, the expanded expression is:
The final temperature of the system is: