A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magnetic field 2

Question

A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magnetic field 2 cm from the center of the wire? A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magnetic field 4 cm from the center of the wire

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Khang Minh 1 month 2021-08-02T18:57:04+00:00 1 Answers 3 views 0

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    2021-08-02T18:58:11+00:00

    Answer:

    a) B = 1.99 x 10⁻⁴ Tesla

    b) B = 0.88 x 10⁻⁴ Tesla

    Explanation:

    According to Biot – Savart Law, the magnetic field due to a currnt carrying straight wire is given as:

    B = μ₀ I L/4πr²

    where,

    μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹

    I = current = 2 A

    L = Length of wire = 40 cm = 0.4 m

    a)

    r = radius of magnetic field = 2 cm = 0.02 m

    Therefore,

    B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.02 m)²

    B = 1.99 x 10⁻⁴ Tesla

    b)

    r = radius of magnetic field = 3 cm = 0.03 m

    Therefore,

    B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.03 m)²

    B = 0.88 x 10⁻⁴ Tesla

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