A 4.88 x 10-6 C charge moves 265 m/s parallel (at 0°) to a magnetic field of 0.0579 T. What is the magnetic force

Question

A 4.88 x 10-6 C charge moves 265 m/s

parallel (at 0°) to a magnetic field of

0.0579 T. What is the magnetic force

on the charge?

in progress 0
Thạch Thảo 2 weeks 2021-07-22T06:50:14+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-07-22T06:51:17+00:00

    Answer:

    0 newtons

    Explanation:

    When a moving charge is parallel to the magnetic field, it feels no Magnetic force at all.

    Even if the Magnetic Field is 100,000,000 Tesla!

    0
    2021-07-22T06:51:17+00:00

    Answer:

    F=0N

    Explanation:

    From the question we are told that:

    Charge Q=4.88 x 10-6 C

    Velocity v= 265m/s

    Angle \theta =0 \textdegree

    Magnetic field B=0.0579T

    Generally the equation for Force is mathematically given by

     F=Q(\=v*\=B)

     F=qvBsin\theta

    Therefore

     F=qvBsin0 \textdegree

     F=0N

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