A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If a

Question

A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?

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Nem 7 months 2021-07-18T00:28:27+00:00 1 Answers 1 views 0

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    2021-07-18T00:29:45+00:00

    Answer:

    K.E = 163 J

    Explanation:

    From the question we are told that:

    Mass m=4.1kg

    Height h=4m

    Speed V=1m/s

    Angle \theta= 2 \textdegree

    Generally the equation for K.E is mathematically given by

    Since

    The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

    Therefore

     K.E=mgH + 0.5mV^2

     K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5

     K.E = 163 J

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