A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the maximum veloc

Question

A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the maximum velocity of the mass

in progress 0
King 1 month 2021-08-14T06:11:53+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-08-14T06:13:08+00:00

    Answer:

    velocity = 2.62m/s

    Explanation:

    950= (4 x A)/0.12

    950 x 0.12 = 4 x A

    114 = 4 x A

    A = 114/4

    A = 28.5m/s²

    • U²=2as
    • U² = 2 x 28.5 x 0.12
    • U² = 6.84
    • U = √6.84
    • U = 2.62m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )