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A 38.5 kg man is in an elevator accelerating downward. A normal force of 343 N pushes up on him. What is his acceleration?
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Answers ( )
Answer:
F = m*(g – a) →
a = g – F/m = 0.891 m/s² downward
Explanation:
If elevator was stationary, the normal force of elevator floor on man* would be = mg
mg = (38.5)(9.81) ≈ 378 N.
If elevator is accelerating downward the floor is accelerating away from man and so the normal force will be less than man’s weight by: 378 – 343 = 35 N.
Hope this helps.