A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from the w

Question

A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from
the wire.

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bonexptip 1 year 2021-09-03T17:56:42+00:00 1 Answers 15 views 0

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    2021-09-03T17:58:41+00:00

    Answer:

    [tex]1.67\cdot 10^{-5} T[/tex]

    Explanation:

    The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:

    [tex]B=\frac{\mu_0 I}{2\pi r}[/tex]

    where:

    [tex]\mu_0=4\pi \cdot 10^{-7} H/m[/tex] is the vaacuum permeability

    I is the current in the wire

    r is the distance from the wire

    The direction of the magnetic field lines is tangential to concentric circles around the wire.

    In this problem, we have:

    [tex]I=37.9 A[/tex] is the current in the wire

    [tex]r=45.5 cm = 0.455 m[/tex] is the distance  from the wire

    Solving for B, we find the magnitude of the magnetic field:

    [tex]B=\frac{\mu_0 I}{2\pi r}=\frac{(4\pi \cdot 10^{-7})(37.9)}{2\pi (0.455)}=1.67\cdot 10^{-5} T[/tex]

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