A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If the second c

Question

A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If the second car has a mass of 790 kg and a speed of 15.1 m/s right after the collision, what is the velocity of the first car after this sudden collision?

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Latifah 2 weeks 2021-09-01T17:38:43+00:00 1 Answers 0 views 0

Answers ( )

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    2021-09-01T17:40:07+00:00

    Answer:

    +14.0 m/s

    Explanation:

    we have mV + Mv = mU + Mu we solve for U = (mV + Mv – Mu)/m = (328*19.1 + 790*13 – 790*15.1)/328 = 14. Answer

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