A 3 kg rock is swung in a circular path and in a vertical plane on a 0.25 m length string. At the top of the path, the angular velocity is 1

Question

A 3 kg rock is swung in a circular path and in a vertical plane on a 0.25 m length string. At the top of the path, the angular velocity is 11 rad/s. What is the tension in the string at that point

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Thanh Thu 4 years 2021-08-13T03:31:09+00:00 1 Answers 4 views 0

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    2021-08-13T03:32:53+00:00

    Answer:

    The tension in the string at that point is 90.75 N

    Explanation:

    Given;

    mass of the object, m = 3 kg

    length of string, r = 0.25 m

    the angular velocity, ω = 11 rad/s

    The tension on string can be equated to the centrifugal force on the object;

    T = mω²r

    Where;

    T is the tension in the string

    m is mass of the object

    ω is the angular velocity

    r is the radius of the circular path

    T = 3 x (11)² x 0.25

    T = 90.75 N

    Therefore, the tension in the string at that point is 90.75 N

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