A 3 kg bowling ball is thrown onto a mattress. If it takes 0.3 seconds to stop the ball using a force of 24 N, what was the initial velocit

Question

A 3 kg bowling ball is thrown onto a mattress. If it takes 0.3 seconds to stop the ball using a force of 24 N, what was the initial velocity of the bowling ball when it first touched the mattress?

in progress 0
Mộc Miên 6 months 2021-07-15T09:53:50+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-07-15T09:55:47+00:00

    Answer:

    2.4 m/s

    Explanation:

    Applying Newton’s second law of motion,

    F = m(v-u)/t………….. Equation 1

    Where F = force exerted on the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time required to stop the ball.

    Note: Since the the ball come to stop, then v = 0 m/s.

    F = -mu/t…………. Equation 2

    make u the subject of the equation

    u = -Ft/m…………. Equation 3

    Given: m = 3 kg, t = 0.3 s, F = 24 N

    Substitute into equation 3

    u = -(24×0.3)/3

    u = -2.4 m/s.

    Note the negative sign tells that the initial velocity of the ball is in opposite direction to the force acting on the ball.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )