A 3.0 kg puck moving at 2.0 m/s strikes a stationary 2.0 kg puck. After the collision, the 3.0 kg puck has a velocity of 0.40 m/s. Use con

Question

A 3.0 kg puck moving at 2.0 m/s strikes a stationary 2.0 kg puck. After the collision, the 3.0 kg puck has a velocity of 0.40 m/s. Use conservation of momentum to find the velocity of the 2.0 kg puck after the collision.

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MichaelMet 2 months 2021-07-30T06:02:57+00:00 1 Answers 1 views 0

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    2021-07-30T06:03:57+00:00

    Answer:

    2.4 m/s

    Explanation:

    Applying,

    The law of conservation of momentum

    Total momentum before collision = Total momentum after collision

    mu+m’u’ = mv+m’v’……………….. Equation 1

    Where m = mass of the moving puck, m’ = mass of the stationary puck, u = initial velocity of the moving puck, u’ = initial velocity of the stationary puck, v = final velocity of the moving puck, v’ = final velocity of the stationary puck.

    make v’ the subject of the equation

    v’ = (mu+m’u’-mv)/m’……………. Equation 2

    From the question,

    Given; m = 3 kg, m’ = 2 kg, u = 2 m/s, u’ = 0 m/s (stationary), v = 0.4 m/s

    Substitute these values into equation 2

    v’ = [(3×2)+(2×0)-(3×0.4)]/2

    v’ = (6-1.2)/2

    v’ = 4.8/2

    v’ = 2.4 m/s

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