A 27.1 kg child is riding a playground merry-go-round that is rotating at 31.6 rev/min. What centripetal force (in N) must she exert to sta

Question

A 27.1 kg child is riding a playground merry-go-round that is rotating at 31.6 rev/min. What centripetal force (in N) must she exert to stay on if she is 1.75 m from its center

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niczorrrr 3 weeks 2021-08-22T19:10:24+00:00 1 Answers 0 views 0

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    2021-08-22T19:11:43+00:00

    Answer:

    F_c = 519.32 N

    Explanation:

    We are given;

    Mass of child; m = 27.1 kg

    Angular velocity;ω = 31.6 rev/min

    Radius;r = 1.75m

    Since we want to find the force in Newton’s, let’s convert the angular velocity to Linear Velocity. The formula is :

    v = r × RPM × 0.10472

    v = 1.75 × 31.6 × 0.10472

    v = 5.791 m/s

    Formula for centripetal force is;

    F_c = mv²/r

    F_c = (27.1 × 5.791²)/1.75

    F_c = 519.32 N

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