A 25 kg child is bouncing on a trampoline, which can be treated as an ideal spring with spring constant 2900 N/m. If the trampoline compress

Question

A 25 kg child is bouncing on a trampoline, which can be treated as an ideal spring with spring constant 2900 N/m. If the trampoline compresses to a maximum of 0.38 m during the bouncing, what is the maximum height that she reaches above the uncompressed surface of the trampoline? You may ignore friction.

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Nguyệt Ánh 4 years 2021-07-27T10:41:08+00:00 1 Answers 24 views 0

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  1. thienthi
    0
    2021-07-27T10:42:37+00:00
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    Answer:

    Explanation:

    Energy store in the compressed trampoline = potential energy of at the maximum height ignoring friction

    energy stored in the trampoline = \frac{1}{2} kx^{2} where k is spring constant and x is the distance compressed  = 0.5 × 2900 × 0.38² = 209.38 J

    209.38 J = 25 × 9.8 × h

    h maximum height attain = 209.38 J / ( 25 × 9.8) = 0.855 m

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