A 25.0 kg bumper car moving to the right at 5.00 m/s overtakes and col- lides clastically with a 35.0 kg bumper car moving to the right

Question

A 25.0 kg bumper car moving to the right at 5.00 m/s overtakes and col-
lides clastically with a 35.0 kg bumper car moving to the right. After the
collision, the 25.0 kg bumper car slows to 1.50 m/s to the right, and the
35.0 kg car moves at 4.50 m/s to the right.
a. Find the velocity of the 35 kg bumper car before the collision.
.b. Verify your answer by calculating the total kinetic energy before and
after the collision.​

in progress 0
Phúc Điền 3 days 2021-07-21T22:36:21+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-21T22:37:45+00:00

    Explanation:

    This problem bothers elastic collision.

    Given data

    Mass m1= 25kg

    Initial velocity u1= 5m/s

    Final velocity v1= 1.5m/s

    Mass m2= 35kg

    Initial velocity u2=?

    Final velocity v2 = 4.5m/s

    A. To find the initial velocity of the 35kg car, let us Apply the principle of conservation of energy

    m1u1+m2u2= m1v1+m2v2

    25*5+ 35*u2= 25*1.5+ 35*4.5

    125+35u2= 37.5+157.5

    125+35u2=195

    35u2= 195-125

    35u2= 70

    u2= 2m/s

    The initial velocity is 2m/s

    B. Totally not kinetic energy before impact

    KE= 1/2m1u1²+ 1/2m2u2²

    KE= (25*5²)/2+ (35*2²)/2

    KE= 625/2 +140/2

    KE= 312.5+70

    KE= 382.5J

    Total kinetic energy after impact

    KE=1/2m1v1²+ 1/2m2v2²

    KE= (25*1.5²)/2 +(35*4.5²)/2

    KE= 56.25/2 +708.75/2

    KE=28.125 +354.375

    KE= 382.5J

    We can see that energy is conserved

    Kinetic energy before and after impact remains unchanged

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )