A 2 kg book is pushed from rest to a final velocity of 3 m/s. The book travels 2 m. How much force was the book pushed with

Question

A 2 kg book is pushed from rest to a final velocity of 3 m/s. The book travels 2 m. How much force was the book pushed with

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Mộc Miên 2 months 2021-07-23T13:37:08+00:00 2 Answers 2 views 0

Answers ( )

    0
    2021-07-23T13:38:12+00:00

    Explanation:

    first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s

    now using the 3rd law of motion

    v^2=u^2+2as

    0=9+2a2

    a= -9/4m/s^2

    now force=mass×accelration

    =2kg×(-9/4)m/s^2

    =4.5 N

    4.5 newton force applied on the book!

    ✌️:)

    0
    2021-07-23T13:38:34+00:00

    Answer:

    4.5N

    Explanation:

    Step 1:

    Data obtained from the question:

    Mass (m) = 2Kg

    Initial velocity (U) = 0

    Final Velocity (V) = 3m/s

    Distance travelled (s) = 2m

    Force (F) =?

    Step 2:

    Determination of the acceleration of the book. This is illustrated below:

    Using V^2 = U^2 + 2as, the acceleration (a) can be obtained as follow:

    V^2 = U^2 + 2as

    3^2 = 0 + 2 x a x 2

    9 = 4a

    Divide both side by the coefficient of a i.e 4

    a = 9/4

    a = 2.25m/s2

    Step 3:

    Determination of the force applied. This is illustrated below:

    Force = Mass x Acceleration

    F = m x a

    F = 2 x 2.25

    F = 4.5N

    Therefore, a force of 4.5N was used to push the book.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )