A 2.2 kg, 20-cm-diameter turntable rotates at 80 rpm on frictionless bearings. Two 600 g blocks fall from above, hit the turntable simultane

Question

A 2.2 kg, 20-cm-diameter turntable rotates at 80 rpm on frictionless bearings. Two 600 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable’s angular velocity, in rpm, just after this event?

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Gia Bảo 2 weeks 2021-07-19T14:25:24+00:00 1 Answers 2 views 0

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    2021-07-19T14:26:31+00:00

    Answer:

    w_2=38.3rpm

    Explanation:

    From the question we are told that:

    Mass of turntable M=2.2kg

    Diameter of turntable d=20cm=>0.2m

    Angular Velocity \omega =80rpm

    Mass of Blocks M_b=600g=>0.6kg

    Generally the equation for inertia is mathematically given by

    Initial scenario at \omega=80rpm

     I_1=\frac{1}{2}mR^2

     I_1=\frac{1}{2}*2.2*0.1^2

     I_1=0.11kgm^2

    Final scenario

     I_2=I_1+2mR^2

     I_2=0.011+(2*0.6*0.12)

     I_2=0.023

    Generally the equation for The relationship between Angular velocity and inertia is mathematically given by

     I_1w_1=I_2w_2

     w_2=\frac{I_1 \omega}{I_2}

     w_2=\frac{0.011*80}{0.023}

     w_2=38.3rpm

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