A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an average friction

Question

A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an average friction force of 4.0 ✕ 103 N impedes the motion, find the speed of the car at the bottom of the driveway.

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Adela 6 months 2021-08-04T13:19:02+00:00 1 Answers 23 views 0

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    2021-08-04T13:20:28+00:00

    Answer:

    3.9 m/s

    Explanation:

    We are given that

    Mass of car,m=2.1\times 10^3 kg

    Initial velocity,u=0

    Distance,s=5.9 m

    \theta=19^{\circ}

    Average friction force,f=4.0\times 10^3 N

    We have to find the speed of the car at the bottom of the driveway.

    Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

    Where g=9.8 m/s^2

    Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

    v=\sqrt{2as}

    v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

    v=3.9 m/s

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