A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.3-T magnetic field. The loop is rotated so that its plane is para

Question

A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.3-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.18 s . What is the average induced emf in the loop? Express your answer to two significant figures and include the appropriate units.

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Dulcie 4 years 2021-09-04T07:22:49+00:00 1 Answers 11 views 0

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  1. Calantha
    0
    2021-09-04T07:24:00+00:00
    Reply

    Answer:

    0.2v

    Explanation:

    Data given,

    Diameter=18.5cm

    Hence we can calculate the radius as D/2=18.5/2=9.25cm

    radius=9.25cm/100=0.0925m

    The area is calculated as

    area=\pi r^{2}\\Area=0.0925^{2}*\pi \\Area=0.02688m^{2}\\

    magnetic field, B=1.3T

    time,t=0.18s

    The flux is expressed as

    flux=BAcos\alpha \\

    since the loop is parallel, the angle is 0

    Hence we can calculate the flux as

    flux=1.3*0.02688cos(0)\\flux=0.0349Wb\\

    to determine the emf induced in the loop, we use Faraday law

    E=-N\frac{d(flux)}{dt}\\ E=-0.0349/0.18\\E=0.19V\\E=-0.2v

    Note the voltage is not negative but the negative sign shows the current flows in other to oppose the flux

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