A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the merry-go-round

Question

A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the merry-go-round as a solid cylinder and determine the net work needed for this acceleration.

in progress 0
Thu Thủy 5 years 2021-07-15T15:43:08+00:00 1 Answers 100 views 0

Answers ( )

  1. MichaelMet
    0
    2021-07-15T15:44:52+00:00
    Reply

    Solution :

    Given data :

    Mass of the merry-go-round, m= 1640 kg

    Radius of the merry-go-round, r = 7.50 m

    Angular speed, $\omega = \frac{1}{8}$  rev/sec

                                 $=\frac{2 \pi \times 7.5}{8}$  rad/sec

                                  = 5.89 rad/sec

    Therefore, force required,

    $F=m.\omega^2.r$

       $$=1640 \times (5.89)^2 \times 7.5  

       = 427126.9 N

    Thus, the net work done for the acceleration is given by :

    W = F x r

       = 427126.9 x 7.5

       = 3,203,451.75 J

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )