A 1510 kg car is experiencing a 2650 N friction force from the road. What force must be applied to the car in order for the car to move for

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A 1510 kg car is experiencing a 2650 N friction force from the road. What force must be applied to the car in order for the car to move forward with a constant velocity of 50.0 km/hr?

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Hải Đăng 2 months 2021-08-02T08:53:52+00:00 1 Answers 1 views 0

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    2021-08-02T08:55:24+00:00

    Answer:

    The force that must be applied to maintain a constant velocity is equal o the friction force which is 2,650 N

    The total force required from rest is (2,650·t + 20,972.\overline 2)/t N

    Explanation:

    The given data of the car in motion are;

    The mass of the car, m = 1,510 kg

    The force of friction from the road, F_f = 2,650 N

    When the car is moving at 50.0 km/hr, we have;

    v = 50.0 km/hr = 250/9 m/s ≈ 13.88889 m/s

    According to Newton’s first Law of motion, a body will continue in a state of rest or in uniform motion along a straight line unless acted on by a force

    The force acting on the car in motion = 2,650 N

    When the car is moving at a constant velocity, the forces acting on the  car are in equilibrium and the net force is zero

    Therefore;

    The magnitude of the force that will keep the car moving at a constant velocity = The friction force of the road = 2,650 N

    The direction of the force = In the direction of motion of the car

    Where the time it takes the car to accelerate from rest to 50.0 km/hr = t seconds, we have;

    The force required to move at a constant speed = 1,510 kg × (250/9 m/s – 0)/t s = 20,972.\overline 2/t N

    The total force required to move forward with a constant velocity of 50.0 km/hr becomes 20,972.\overline 2/t N + 2,650 N = (2,650·t + 20,972.\overline 2)/t N

    Where;

    t = The time it takes the car to reach 50.0 km/hr from rest.

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