A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and

Question

A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and causes it to move in the opposite direction with a velocity of 10.0 m/s. What impulse was delivered to the pinball by the launcher?

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Thông Đạt 2 weeks 2021-09-02T09:25:56+00:00 1 Answers 0 views 0

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    2021-09-02T09:27:19+00:00

    Answer:

      I = 1.8 N s,  it is directed towards the right  

    Explanation:

    For this exercise we use the relationship between momentum and moment

             I = Δp

             F t = p_f – p₀

    in this case the initial velocity is v₀ = – 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

              I = m (v_f – v₀)

    let’s calculate

             I = 0.150 (10.0 – (-2.0))

             I = 0.150 (10 + 2)

             I = 1.8 N s

    as the impulse is positive it is directed towards the right

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )