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## A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and

Question

A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and causes it to move in the opposite direction with a velocity of 10.0 m/s. What impulse was delivered to the pinball by the launcher?

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Physics
2 weeks
2021-09-02T09:25:56+00:00
2021-09-02T09:25:56+00:00 1 Answers
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## Answers ( )

Answer:I = 1.8 N s, it is directed towards the right

Explanation:For this exercise we use the relationship between momentum and moment

I = Δp

F t = p_f – p₀

in this case the initial velocity is v₀ = – 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

I = m (v_f – v₀)

let’s calculate

I = 0.150 (10.0 – (-2.0))

I = 0.150 (10 + 2)

I = 1.8 N s

as the impulse is positive it is directed towards the right