A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initia

Question

A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initially at rest and with brakes released. What is the speed of the two cars after collision?

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Nguyệt Ánh 5 months 2021-08-18T14:43:33+00:00 1 Answers 18 views 0

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    2021-08-18T14:44:36+00:00

    Answer:

    V = 1.578m/s

    Explanation:

    (Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

    (13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

    60750 + 0 = (38500)V

    60750 = 38500V

    V = 60750/38500

    V = 1.578m/s

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