A 125 ml sample of gas is at STP how many moles of gas are in the sample

Question

A 125 ml sample of gas is at STP how many moles of gas are in the sample

in progress 0
Thành Đạt 6 months 2021-08-04T09:24:27+00:00 2 Answers 9 views 0

Answers ( )

    0
    2021-08-04T09:26:10+00:00

    Answer:

    5.58*10⁻³ moles of gas are in the sample.

    Explanation:

    The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

    Being 1000 mL equivalent to 1 L, then 125 mL is equal to 0.125 L. Then you can apply the following rule of three: if by STP conditions 22.4 L are occupied by 1 mole, 0.125 L are occupied by how many moles?

    amount of moles=\frac{0.125 L*1 mole}{22.4 L}

    aomunt of moles= 5.58*10⁻³ moles

    5.58*10⁻³ moles of gas are in the sample.

    0
    2021-08-04T09:26:12+00:00

    Answer:

    5.58×10⁻³ moles of gas

    Explanation:

    There is a rule that says, that 1 mol of any gas, at STP is contained at 22.4L of volume.

    We can apply a conversion factor

    0.125 L . 1 mol / 22.4 L = 5.58×10⁻³ moles

    Notice we converted volume from mL to L

    We can also aply the Ideal Gases Law.

    At STP we have 1 atm of pressure and 273.15K of T°

    We replace data: 0.125 L . 1 atm = n . 0.082 . 273.15K

    (0.125 L . 1 atm) / (0.082 . 273.15 K) = n

    n = 5.58×10⁻³ moles

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )