A 125.0-g sample of a metal heated to 100.0 ∘C and placed in a calorimeter that contains 250.0 g of water. The temperature rises from 24.3 ∘

Question

A 125.0-g sample of a metal heated to 100.0 ∘C and placed in a calorimeter that contains 250.0 g of water. The temperature rises from 24.3 ∘C to 27.2 ∘C. What is the specific heat capacity of the metal? Ignore the calorimeter in your analysis. Group of answer choices

in progress 0
RI SƠ 5 months 2021-08-16T05:21:10+00:00 1 Answers 5 views 0

Answers ( )

    0
    2021-08-16T05:23:04+00:00

    Answer:

    0.333J/g°C is the specific heat of the metal

    Explanation:

    The heat that the metaal gives is equal to the heat that water is absorbing. The equation is:

    S(metal)*ΔT(metal)*Mass(metal) = S(H2O)*ΔT(H2O)*Mass(H2O)

    Where S is specific heat, ΔT is change in temperature and mass the mass in grams of the metal and water.

    Replacing:

    S(metal)*(100.0°C-27.2°C)*125.0g = 4.184J/g°C*(27.2°C-24.3°C)*250.0g

    S(metal) = 4.184J/g°C*(27.2°C-24.3°C)*250.0g / (100.0°C-27.2°C)*125.0g

    S(metal) = 0.333J/g°C is the specific heat of the metal

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )