A 12.0 volt battery is connected in a series to 4 identical 5.00 ohm resistors connected in parallel to each other. What is the current thro

Question

A 12.0 volt battery is connected in a series to 4 identical 5.00 ohm resistors connected in parallel to each other. What is the current through the battery?

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MichaelMet 1 year 2021-08-31T01:43:28+00:00 2 Answers 8 views 0

Answers ( )

    0
    2021-08-31T01:44:40+00:00

    Answer:

    9.6 Amperes

    Explanation:

    1. since the resistors are connected in parallel connection the equivalent resistance is

    1/R = 1 /5 + 1/5 + 1/5 + 1/5

    solving for R we get 5/4 ohms

    then from V=IR

    I = V/R

    I=12/(5/4)

    hence I= 9.6 Amperes

    0
    2021-08-31T01:44:58+00:00

    Answer:

    R =4•Rₒ = 4•50 = 200 Ω

    Ohm’s law

    I =U/R = 12/200 =0.06 A

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