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A 12.0 volt battery is connected in a series to 4 identical 5.00 ohm resistors connected in parallel to each other. What is the current thro
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Answers ( )
Answer:
9.6 Amperes
Explanation:
1/R = 1 /5 + 1/5 + 1/5 + 1/5
solving for R we get 5/4 ohms
then from V=IR
I = V/R
I=12/(5/4)
hence I= 9.6 Amperes
Answer:
R =4•Rₒ = 4•50 = 200 Ω
Ohm’s law
I =U/R = 12/200 =0.06 A