A 12.0-g sample of carbon from living matter decays at the rate of 162.5 decays/minute due to the radioactive 14C in it. What will be the de

Question

A 12.0-g sample of carbon from living matter decays at the rate of 162.5 decays/minute due to the radioactive 14C in it. What will be the decay rate of this sample in 1000 years? What will be the decay rate of this sample in 50000 years?

in progress 0
Minh Khuê 6 months 2021-08-06T13:01:25+00:00 1 Answers 14 views 0

Answers ( )

    0
    2021-08-06T13:03:16+00:00

    Answer:

    a)143.8 decays/minute

    b)0.41 decays/minute

    Explanation:

    From;

    0.693/t1/2 = 2.303/t log (Ao/A)

    Where;

    t1/2=half-life of C-14= 5670 years

    t= time taken to decay

    Ao= activity of a living sample

    A= activity of the sample under study

    a)

    0.693/5670 = 2.303/1000 log(162.5/A)

    1.22×10^-4 = 2.303×10^-3 log(162.5/A)

    1.22×10^-4/2.303×10^-3 = log(162.5/A)

    0.53 × 10^-1 = log(162.5/A)

    5.3 × 10^-2 = log(162.5/A)

    162.5/A = Antilog (5.3 × 10^-2 )

    A= 162.5/1.13

    A= 143.8 decays/minute

    b)

    0.693/5670 = 2.303/50000 log(162.5/A)

    1.22×10^-4 = 4.61×10^-5 log(162.5/A)

    1.22×10^-4/4.61×10^-5 = log(162.5/A)

    0.26 × 10^1 = log(162.5/A)

    2.6= log(162.5/A)

    162.5/A = Antilog (2.6 )

    A= 162.5/398.1

    A= 0.41 decays/minute

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )