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## A 100-turn, 7.0-cm-diameter coil is made of 0.50-mm-diameter copper wire. A magnetic field is perpendicular to the coil. At what rate must B

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## Answers ( )

Answer:The rate of increase of the magnetic field is

0.0311 T/s.Explanation:Given;

number of turns of the coil, N = 100 turn

diameter of the coil, D = 7.0 cm = 0.07 m

diameter of the copper wire, d = 0.5 mm = 0.5 x 10⁻³ m

induced current, I = 2.0 A

The induced emf is calculated as;

is the rate of increase of the magnetic field, B

R is the resistance of the copper wire

Where; ρ is the resistivity of copper wire = 1.68 x 10⁻⁸ Ωm

Therefore, the rate of increase of the magnetic field is

0.0311 T/s.