A 100-N force has a horizontal component of 80 N and a vertical component of 60 N. The force is applied to a cart on a level frictionless fl

Question

A 100-N force has a horizontal component of 80 N and a vertical component of 60 N. The force is applied to a cart on a level frictionless floor. The cart starts from rest and moves 2.0 m horizontally along the floor due to this force. What is the cart’s final kinetic energy

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Calantha 6 months 2021-07-26T22:29:09+00:00 2 Answers 49 views 0

Answers ( )

    0
    2021-07-26T22:30:52+00:00

    Answer:

    The final kinetic for the car is 160 J

    Explanation:

    Given:

    x = 2 m

    Fx = 80 N

    There is no work for the vertical component, and the initial kinetic is zero, thus, the final kinetic energy is:

    EKfinal = Fx * x = 80 * 2 = 160 J

    0
    2021-07-26T22:30:55+00:00

    Answer: 160 J

    Explanation:

    To solve this question, we would have to ignore the vertical component of the applied force. The focus would only be on the horizontal component of 80 N. We know that work is defined as force over distance(w = f*d)

    On multiplying the force by the distance, we have:

    KE = 80 * 2.0

    KE = 160 Nm = 160 kgm²/s²

    KE = 160 Joules.

     Therefore, we simply say that the cart has a final Kinetic Energy of 160 Joules.

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