A 100.0g sample of nickel is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water at 25.0 oC. A

Question

A 100.0g sample of nickel is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water at 25.0 oC. After the metal cools, the final temperature of the metal and the water is 29.8 oC. Calculate the specific heat capacity of nickel from these experimental data, assuming that no heat escapes to the surroundings or is transferred to the calorimeter. Specific heat of water

in progress 0
Thành Đạt 3 years 2021-08-23T08:59:14+00:00 1 Answers 13 views 0

Answers ( )

  1. linhdan
    0
    2021-08-23T09:00:41+00:00
    Reply

    Answer:

    0.429 J/g.°C

    Explanation:

    Step 1: Calculate the heat absorbed by the water (Qw)

    We will use the following expression.

    Q = c × m × ΔT

    where,

    c: specific heat capacity

    m: mass

    ΔT: change in the temperature

    Qw = 4.184 J/g.°C × 150. g × (29.8°C-25.0°C) = 3012 J

    Step 2: Calculate the heat released by the sample of nickel

    According to the law of conservation of energy, the sum of the heat lost by the sample of nickel and the heat absorbed by the water is zero.

    Qw + QNi = 0

    QNi = -Qw = -3012 J

    Step 3: Calculate the specific heat capacity of nickel

    We will use the following expression.

    QNi = c × m × ΔT

    c = QNi/m × ΔT

    c = -3012 J/100.0 g × (29.8°C-100.0°C) = 0.429 J/g.°C

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )