A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.30 Ω is in a 1.0 mT magnetic field, with the coil oriented for maxi

Question

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.30 Ω is in a 1.0 mT magnetic field, with the coil oriented for maximum flux. The coil is connected to an uncharged 3.0 μF capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field.

Afterward, what is the voltage across the capacitor?

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3 days 2021-07-19T02:23:31+00:00 1 Answers 1 views 0

The voltage across the capacitor = 0.8723 V

Explanation:

From the question, it is said that the coil is quickly pulled out of the magnetic field. Therefore , the final magnetic flux linked to the coil is zero.

The change in magnetic flux linked to this coil is:

= 0 – BA cos 0°

Using Faraday’s Law; the induced emf on N turns of coil is;

Also; the induced current I =

The voltage across the capacitor can now be determined as:

=

= 0.8723 V