a 10 kg block is attached to a light chord that is wrapped around the pulley of an electric motor. at what rate is the motor doing work when

Question

a 10 kg block is attached to a light chord that is wrapped around the pulley of an electric motor. at what rate is the motor doing work when it is pulling the block upward w an instantaneous speed of 3 m/s and an upward acc of 2 m/s^2?

in progress 0
Ladonna 5 days 2021-07-19T14:13:10+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-07-19T14:14:34+00:00

    Answer:

    The rate of work is 360 W

    Explanation:

    Given:

    Speed of block v = 3 \frac{m}{s}

    Upward acceleration of block a = 2 \frac{m}{s^{2} }

    Mass of block m = 10 kg

    First Find the force act on block due to gravity

      F = M (a + g)

    Where g = 10 \frac{m}{s^{2} }

      F = 10 \times (10+2)

      F = 120 N

    For finding at what rate motor doing work when it is pulling the block upward,

      P = F.v

      P = 120 \times 3

      P = 360 W

    Therefore, the rate of work is 360 W

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )