A 10.0 L tank contains 0.329 kg of helium at 28.0 ∘C. The molar mass of helium is 4.00 g/mol . Part A How many moles of helium are in the ta

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A 10.0 L tank contains 0.329 kg of helium at 28.0 ∘C. The molar mass of helium is 4.00 g/mol . Part A How many moles of helium are in the tank? Express your answer in moles.

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  1. Answer:

    82.25 moles of He

    Explanation:

    From the question given above, the following data were obtained:

    Volume (V) = 10 L

    Mass of He = 0.329 Kg

    Temperature (T) = 28.0 °C

    Molar mass of He = 4 g/mol

    Mole of He =?

    Next, we shall convert 0.329 Kg of He to g. This can be obtained as follow:

    1 Kg = 1000 g

    Therefore,

    0.329 Kg = 0.329 Kg × 1000 g / 1 Kg

    0.329 Kg = 329 g

    Thus, 0.329 Kg is equivalent to 329 g.

    Finally, we shall determine the number of mole of He in the tank. This can be obtained as illustrated below:

    Mass of He = 329 g

    Molar mass of He = 4 g/mol

    Mole of He =?

    Mole = mass / molar mass

    Mole of He = 329 / 4

    Mole of He = 82.25 moles

    Therefore, there are 82.25 moles of He in the tank.

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