A 1.50-V battery supplies 0.204 W of power to a small flashlight. If the battery moves 8.33 1020 electrons between its terminals during the

Question

A 1.50-V battery supplies 0.204 W of power to a small flashlight. If the battery moves 8.33 1020 electrons between its terminals during the time the flashlight is in operation, how long was the flashlight used

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bonexptip 3 years 2021-08-21T20:26:58+00:00 1 Answers 6 views 0

Answers ( )

  1. haidang
    0
    2021-08-21T20:28:21+00:00
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    Answer:

    981.41 secs

    Explanation:

    Parameters given:

    Voltage, V = 1.5V

    Power, P = 0.204W

    Number of electrons, n = 8.33 * 10^20

    First, we calculate the current:

    P = I*V

    I = P/V

    I = 0.204/1.5 = 0.136A

    The total charge of 8.33 * 10^20 electrons is:

    Q = 8.33 * 10^20 * 1.6023 * 10^(-19)

    Q = 133.47 C

    Current, I, is given as:

    I = Q/t

    => t = Q/I

    t = 133.47/0.136 = 981.41 secs

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