A 1.45 kg 1.45 kg falcon catches a 0.415 kg 0.415 kg dove from behind in midair. What is their velocity after impact if the falcon’s velocit

Question

A 1.45 kg 1.45 kg falcon catches a 0.415 kg 0.415 kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is initially 26.5 m/s 26.5 m/s and the dove’s velocity is 4.35 m/s 4.35 m/s in the same direction?

in progress 0
Xavia 4 years 2021-07-28T01:19:33+00:00 1 Answers 10 views 0

Answers ( )

  1. Orla
    0
    2021-07-28T01:21:22+00:00
    Reply

    Answer: The velocity is 21.5m/s

    Explanation:

    Let’s call:

    M1 and V1 as the mass and velocity of the falcon:

    M1 = 1.45kg

    V1 = 26.5m/s

    M2 and V2 as the mass and velocity of the dove:

    M2 = 0.415kg

    V2 = 4.35m/s

    Where both velocities are positive because both animals move in the same direction.

    We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:

    V = (V1*M1 + V2*M2)/(M1 + M2)

    V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )