A 1.44-mole sample of an ideal gas is allowed to expand at a constant temperature of 258 K. The initial volume is 14.5 L and the final volum

Question

A 1.44-mole sample of an ideal gas is allowed to expand at a constant temperature of 258 K. The initial volume is 14.5 L and the final volume is 27.0 L. How much work does the gas perform on its container? Let the ideal-gas constant R = 8.314 J/(mol • K).

1920 J

2340 J

1550 J

1040 J

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Khánh Gia 5 months 2021-08-21T07:08:41+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-21T07:10:23+00:00

    Answer:

    1920 J

    Explanation:

    Answer:

    19.6 L

    Explanation:

    In this process we have an isothermal process, a transformation in which the temperature of the gas remains constant.

    In an isothermal process, the work done by the ideal gas on the surrounding is:

    W=nRT ln\frac{V_f}{V_i}

    where:

    n is the number of moles of the gas

    R is the gas constant

    T is the absolute temperature of the gas

    V_i is the initial volume of the gas

    V_f is the final volume

    In this problem, we have:

    n = 1.44 mol

    T = 258 K is the gas temperature

    V_i=14.5 L is the initial volume of the gas

    V_f=27.0 L is the final volume

    Solving the equation for W, we find the work done by the gas:

    W=(1.44)(8.314)(258)ln\frac{27.0}{14.5}=1920 J

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