a, ( x – 1/2 )^2 = 1/9 b, /x + 3/ + 2 = 6

Question

a, ( x – 1/2 )^2 = 1/9
b, /x + 3/ + 2 = 6

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Thông Đạt 9 months 2021-04-15T12:11:59+00:00 2 Answers 33 views 0

Answers ( )

    0
    2021-04-15T12:13:06+00:00

    @Meoss_

    * a/ ( x – 1/2 )^2 = 1/9

    ⇒ (x-1/2)^2 = (-+1/3)^2

    ⇒ x-1/2 = +-1/3

    ⇒ x= 1/3 + 1/2 hoặc x= -1/3 + 1/2

    ⇒ x= 5/6 hoặc x=1/6

      Vậy x = 5/6 hoặc x=1/6

    * b/ /x + 3/ + 2 = 6

    ⇒ /x+3/             = 6 – 2

    ⇒ /x+3/             = 4

    ⇒ \(\left[ \begin{array}{l}x+3=4\\-(x+3)=4\end{array} \right.\) 

    ⇒ \(\left[ \begin{array}{l}x=4-3\\x=3+4\end{array} \right.\) 

    ⇒ \(\left[ \begin{array}{l}x=1\\x=-7\end{array} \right.\) 

      Vậy x=1 hoặc x=-7

     

    0
    2021-04-15T12:13:30+00:00

    Đáp án + Giải thích các bước giải:

    `a)`

         `(x – 1/2)^2 = 1/9`

    `⇔(x – 1/2)^2 = (±1/3)^2`

    `⇔`\(\left[ \begin{array}{l}x-\dfrac{1}{2} =\dfrac{1}{3} \\x – \dfrac{1}{2} =\dfrac{-1}{3}\end{array} \right.\) 

    `⇔` \(\left[ \begin{array}{l}x=\dfrac{5}{6}\\x=\dfrac{1}{6}\end{array} \right.\)  

    `b)`

         `|x + 3| + 2 = 6`

    `⇔ |x + 3| = 6 – 2`

    `⇔|x + 3| = 4`

    `⇔` \(\left[ \begin{array}{l}x + 3 = 4\\x + 3 = -4\end{array} \right.\) 

    `⇔` \(\left[ \begin{array}{l}x=1\\x=-7\end{array} \right.\) 

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )