A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the bat with a

Question

A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the bat with a speed of 25 meters per second. What is the magnitude of the average force exerted by the ball on the bat

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Xavia 2 months 2021-07-29T06:16:12+00:00 1 Answers 4 views 0

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    2021-07-29T06:17:58+00:00

    Answer:

    75 Newtons.

    Explanation:

    From Newton’s second law of motion,

    F = m(v-u)/t………………. Equation 1

    Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time

    Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.

    Substitute into equation 1

    F = 0.6(25-0)/0.2

    F = 3(25)

    F = 75 Newton.

    Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.

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