Share

## A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the bat with a

Question

A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the bat with a speed of 25 meters per second. What is the magnitude of the average force exerted by the ball on the bat

in progress
0

Physics
2 months
2021-07-29T06:16:12+00:00
2021-07-29T06:16:12+00:00 1 Answers
4 views
0
## Answers ( )

Answer:75 Newtons.Explanation:From Newton’s second law of motion,

F = m(v-u)/t………………. Equation 1

Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time

Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.

Substitute into equation 1

F = 0.6(25-0)/0.2

F = 3(25)

F = 75 Newton.

Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.