A 0.54-kg ball is thrown vertically upward with an initial speed of 15.5 m/s. What is the potential energy of the ball when it has travelled

Question

A 0.54-kg ball is thrown vertically upward with an initial speed of 15.5 m/s. What is the potential energy of the ball when it has travelled one-quarter of the distance to its maximum height

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Adela 4 years 2021-09-01T15:43:05+00:00 1 Answers 16 views 0

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  1. trucchi
    0
    2021-09-01T15:44:44+00:00
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    Answer:

    16.2J

    Explanation:

    At the maximum height v = 0

    V ^2= u^2 – 2gh (- because since the ball is going upward)

    h = u^2 – v^2 / 2g

    15.5^2 /20

    h = 12.0125

    h = 12m

    At one quarter of the distance 1/4 × 12 = 3m

    Potential energy = mgh

    = 0.54 × 10× 3

    = 16.2J

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