A 0.43 m long and 0.43 m wide loop is moved at a constant velocity of 0.15 m/s into a perpendicular constant magnetic field of 0.31 T. Calcu

Question

A 0.43 m long and 0.43 m wide loop is moved at a constant velocity of 0.15 m/s into a perpendicular constant magnetic field of 0.31 T. Calculate the magnitude of the induced voltage in the loop.

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Philomena 6 months 2021-09-05T03:51:41+00:00 1 Answers 0 views 0

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    2021-09-05T03:52:46+00:00

    Answer:

    The magnitude of the induced voltage in the loop is 20 mV.

    Explanation:

    given;

    length of loop, L = 0.43 m

    width of loop,w = 0.43 m

    velocity of moved loop, v = 0.15m/s

    magnetic field strength,B = 0.31 T

    To determine the magnitude of the induced voltage in the loop, we apply Faraday’s law;

    magnitude induced E.M.F = BLv

    magnitude induced E.M.F = 0.31 x 0.43 x 0.15 = 0.02 V = 20 mV

    Therefore, the magnitude of the induced voltage in the loop is 20 mV.

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